判断密码强度小程序

import random

def have_number(password_str):
    numbers = {'0','1','2','3','4','5','6','7','8','9'}
    return set(password_str) & numbers

def have_letter(password_str):
    letters = set('abcdefghijklmnopqrstuvwxyz')
    return letters & set(password_str.lower())

def makenumberstr():
    """随机产生一个3到10位的数字字符串"""
    n = '0123456789'
    return "".join( [random.choice(n) for _ in range(random.randint(3,10))])

def makalphastr():
    """随机产生一个3到10位的字母字符串"""
    s = 'abcdefghijklmnopqrstuvwxyz'
    return "".join( [random.choice(s) for _ in range(random.randint(3,10))])

def makerandomstr():
    """随机产生一个3到10位的包含数字和字母的字符串"""
    s = '0123456789abcdefghijklmnopqrstuvwxyz'    
    return "".join( [random.choice(s) for _ in range(random.randint(3,10))])

def makepass(level):
    """根据密码强度产生密码"""
    if level == 1:
        p = makerandomstr()
        while len(p)>=8:p = makerandomstr()       
    elif level == 2:               # 如果强度是2，则产生大于或等于8位的仅是数字或字母的密码
        if random.randint(0,1)==0: # 如果是0，产生大于或等于8位的数字密码      
            p = makenumberstr()
            while len(p)<8:p = makenumberstr()
        else:
            p = makalphastr()
            while len(p)<8:p = makalphastr()
    elif level == 3:               # 如果强度是3，则产生大于8位的包含数字和字母的密码
        p = makerandomstr()
        while len(p)<8 or not have_number(p) or not have_letter(p):
              p = makerandomstr()

    return p

for _ in range(10):
    level = random.randint(1,3)
    print(level,makepass(level))